[(16x-4)4-8(3x+2)=12x-5

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Solution for [(16x-4)4-8(3x+2)=12x-5 equation: 



(16x-4)4-8(3x+2)=12x-5

We move all terms to the left:

(16x-4)4-8(3x+2)-(12x-5)=0

We multiply parentheses

64x-24x-(12x-5)-16-16=0

We get rid of parentheses

64x-24x-12x+5-16-16=0

We add all the numbers together, and all the variables

28x-27=0

We move all terms containing x to the left, all other terms to the right

28x=27

x=27/28

x=27/28

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